Then G(oo) contains infinitely many I2-paths. The result is the best possible since there exists a G(oo) for which g(n) > 1/8 n2+ 1/32 n2/ log2n+o(n2/ log2n) and which does not contain any I2-path.
Theorem III. Let G(oo) be such that g(n) \geq 1/4 n2-Cn. Then G(oo) contains an infinite path. This result is best possible in the sense that C can not be replaced by A(n) where A(n) > oo.
Theorem IV. There exists a G(oo) with liminf [g(n) /n2] > {1 \over 4} which does not contain an Ioo-path. But there exists a constant \alpha > 0 such that every G(oo) with liminf [g(n)/n2] > 1/2 -\alpha contains an Ioo-path. Theorem V. If g(n) > 1/2 n2-Cn for infinitely many n then G(oo) contains an infinite complete subgraph. But if we only assume that g(n) > 1/2 n2 -f(n) n for all n where f(n) tends to infinity as slowly as we please then G(oo) does not have to contain an infinite complete graph.
Reviewer: J.Dénes
Classif.: * 05C35 Extremal problems (graph theory)
Index Words: combinatorics
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