for two different primes p1,p2; and let
The main result of this paper, which constitutes a wide generalization of the author's work on abundant numbers (Zbl 010.10303), is that limn > oo N (f; c)/n exists and is a continuous function of c. The case of the abundant numbers is obtained by taking f(m) =
Suppose first f(m) satisfies the more stringent conditions: (3) f(p\alpha) =
(I) For any \epsilon > 0 there exists a \delta such that N(f; c,c+\delta) < \epsilon n for all sufficiently large n;
(II) For any \epsilon,\delta > 0 there exists a P(\epsilon,\delta) such that for P > P(\epsilon,\delta) and all n, the number of integers m \leq n for which f(m)-fp(m) > \delta is less than \epsilon n. The main difficulty lies in the proof of (I), which uses the same idea as the paper already cited.
The author then sketches the proof when (3) is not assumed. As regards (4), he shows that it can be replaced by a weaker condition (4') and that if (4') does not hold, then limn > oo N(f; c)/n =
Reviewer: Davenport (Cambridge)
Classif.: * 11N60 Distribution functions (additive and positive multipl. functions)
Index Words: Number theory
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