[from sth, to sth; amer. than sth; see also: \haslo{different} [from sth, to sth; amer. than sth; see also: distinct, other,
various, several, particular] The case a=1 requires a different approach.
The situation is quite different if we replace H(U) by certain subclasses.
by using a somewhat different method
This idea is very little different from what can already be found in [2].
Our solution is completely different to theirs.
There is another, entirely different, way to see that A=B. Namely, one can first show that......